(3x^2-4x-1)+(8x^2-x+6)=0

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Solution for (3x^2-4x-1)+(8x^2-x+6)=0 equation: 



(3x^2-4x-1)+(8x^2-x+6)=0

We get rid of parentheses

3x^2+8x^2-4x-x-1+6=0

We add all the numbers together, and all the variables

11x^2-5x+5=0

a = 11; b = -5; c = +5;
Δ = b2-4ac
Δ = -52-4·11·5
Δ = -195
Delta is less than zero, so there is no solution for the equation

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